## Complex numbers for IIT-JEE MAINS /ADVANCED

Complex numbers basic concepts-Defining

A number in the form of a + ib, where a, b are real numbers and is called a complex
Number. A Complex Number can also be defined as an ordered pair of real numbers a and b any
may be written as (a, b), where the first number denotes the real part and the second number
denotes the imaginary part. If z = a + ib, then the real part of z is denoted by Re (z) and the
imaginary part by Im(z). A complex number is said to be purely real if Im(z)= 0, and is said to
be purely imaginary if Re(z) = 0. The complex number 0 = 0 + i0 is both purely real and imaginary.
Two complex numbers are said to be equal if and only if their real parts and imaginary parts are
separately equal i.e. a + ib = c + id implies a = c and b = d. However, there is no order relation
between complex numbers and the expressions of the type a + ib < (or > ) c + id are meaningless

Geometrical representation of complex numbers

A complex number z = x + iy, written as an ordered pair (x, y), can be represented by a point P whose Cartesian coordinates are (x, y) referred to axes OX and OY, usually called the real and the imaginary axes.

The plane of OX and OY is called the Argand diagram or the complex plane. Since the origin O lies on both OX and OY, the corresponding complex number z = 0 is both purely real and purely imaginary.

Modulus and Argument of a Complex Number

We define modulus of the complex number z = x + iy as

Trigonometric ( or polar ) from a Complex Number

Remark : Method of finding the principal value of the argument of a complex number z = x + iy.

Unimodular Complex Number

Algebraic Operations with Complex Number

Geometrical Meaning of Product and Division

Let z1 = x1 + i y1 and z2 = x2 + i y2 be two complex numbers represented by the points P1(x1, y1) and P2(x2, y2) respectively. By definition z1 + z2 should be represented by the point (x1 + x2 , y1 + y2 ). This point is the vertex which completes the parallelogram with the line segments joining the origin with OP1 and OP2 as the adjacent sides.
| z1 + z2 | = OP.

Construction for the point representing the product z1 z2

.

Construction for the point representing the quotient z1/z2

Draw the triangle OQ1P directly similar to the triangle OQ2L
The P represents the quotient z1/z2 .

Square Root of a Complex Number

How we get the square root of complex number

Conjugate of a Complex Number

The conjugate of the complex number z = a + ib is defined to be a – ib and i denoted by . In other words is the mirror image of z in the real axis.

Properties of Conjugate, Modulus, Argument

Distance of a complex number z from origin is called the modulus of the complex number z and it is denoted by |z| .

Properties of Arguments

De-Moiver’s Theorem

Application of De Moiver’s Theorem

This is a fundamental theorem and has various applications. Here we will discuss few of these
which are important from the examination point of view

The nth Roots of Unity

Logarithm of Complex Number

CONCEPT OF ROTATION

Geometrical Application

Section Formula

Equation of a straight line

Equation of straight line with the help of coordinate geometry

Equation of Perpendicular Bisector

arg (z – z0) =p  represents a line passing through z0 with slope (making angle p with the positive direction of x-axis).

Equation of a circle

Consider a fixed complex number z0 and let z be any complex number which moves in such a way
that it’s distance from z0 is always equals to ‘r’. This implies z would lie on a circle whose centre is
z0 and radius r. And its equation would | z – z0 | = r

Note :
(i) If we take ‘C’ to be mid–point of A2A1, it can be easily proved that CA.CB = (CA1)2 i.e. | z1 – z0 | | z2 – z0 | = r2, where the point C is denoted z0 and r is the radius of the circle.

(ii) If | z1 – z0 | = | z2 – z0 | hence P(z) would lie on the right bisector of the line A(z1)
and B(z2). Note that in this case z1 and z2 are the mirror images of each other with respect
to the right bisector.

Equation of tangent a given circle at a given point

Some important results

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BASIC RESULTS RELATED TO A QUADRATIC EQUATIONS

The quantity D

• The quadratic equation has real and equal roots if and only if D = 0

• The quadratic equation has real and distinct roots if and only if D > 0

• The quadratic equation has complex roots with non-zero imaginary parts if and only if D < 0 . If p + iq (p and q being real) is a root of the quadratic equation where i = , then p – iq is also a root of the quadratic equation.

CONCEPT OF IDENTITY

If the quadratic equation is satisfied by more than two distinct numbers (real or complex), then it becomes an identity i.e. a = b = c = 0. For example

is satisfied by three value of x which are a, b and c. Hence this is an identity in x.

HOW TO SOlVE RATIONAL INEQUALITIES

In order to solve inequalities of the form

we use the following method:

If x1 and x2 (x1 < x2) are two consecutive distinct roots of a polynomial equation, then within this
interval the polynomial itself takes on values having the same sign. Now find all the roots of the polynomial equations P(x) = 0 and Q(x) = 0. Ignore the common roots and write

Other way of understanding the same concept

• Write the inequality in the correct form. One side must be zero and the other must be in product form
• Find the key or critical values. To find the key/critical values, set the numerator and denominator of the fraction equal to zero and change them in product of linear forms
• Make a sign analysis chart. To make a sign analysis chart, use the key/critical values found in Step 2 to and mention them on line in increasing form.
• Perform the sign analysis. and make wave that give the sign of product
• What is needed acording to that write final answers
• Problems related to rational inequalities with video solutions

CONDITIONS OF COMMON ROOTS FOR TWO QUADRATIC EQUATIONS

For two quadratic equations when one root is common / When both roots are common are given

HOW TO FIND  RANGE OF A RATIONAL EXPRESSION IN X, WHERE X IS REAL

Put the given rational expression equal to y and form the quadratic equation in x.

Find the discriminant D of the quadratic equation obtained in step 1.

Since x is real, therefore, put D   GREATER THAN OR EQUAL TO 0. We get an inequation in y.

Solve the above inequation for y. The range of y so obtained determines the range attained by the given rational expression

The expression ax2 + bx + c is said to be a real quadratic expression in x where a, b, c are real and
a 0. Let f(x) = ax2 + bx + c, where a, b, c R (a 0). f(x) can be re-written as

Therefore y = f(x) represents a parabola whose axis is parallel to the y-axis, with vertex at
A .

(iv)

a < 0 and D< 0
f(x) < 0xR.
In this case the parabola remains concave downwards and always below the x-axis.

RELATION BETWEEN THE ROOTS OF A POLYNOMIAL EQUATION OF DEGREE N AND coefficient

IMPORTANT POINTS

A polynomial equation of degree n has n roots (real or imaginary).

If all the coefficients are real then the imaginary roots occur in pairs i.e., number of imaginary roots is always even.

If the degree of a polynomial equation is odd then the number of real roots will also be odd. It follows that at least one of the roots will be real.

Polynomial in x of degree n can be factorized into a product of linear/quadratic form.

I

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## Probability for IIT-JEE MAINS /ADVANCED

Probability is very important topic for IIT JEE MAINS / ADVANCED.

Its the topic for which understanding is must .

For JEE MAINS its   weightage is 3 to 4%

and for  JEE ADVANCED its weightage is 11 TO 14 %

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To understand this problem of Function  you must know : The concept of composite function

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To understand this problem of Function  you must know : The concept of periodic functions , order pair relation

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To understand this problem of Function  you must know : The concept of mod  functions and simple trigonometric calculations

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To understand this problem of Function  you must know : The concept of even and odd functions and how to deal functional equations

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To understand this problem of Function  you must know : The concept of cubic functions

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To understand this problem of Function  you must know : The concept of composite function

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To understand this problem of Function  you must know : The concept of AP and how we deal functional equations

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To understand this problem of Function  you must know : The concept of composite function

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To understand this problem of Function  you must know : The concept of inverse  function

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To understand this problem of Function  you must know : The concept of peridic function

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To understand this problem of Function  you must know : The concept of greatest integer function

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To understand this problem of Function  you must know : The concept of periodic functions

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